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(x-y+z)²等于多少

解: (X+Y)(X-Y)+(Y-Z)(Y+Z)-(X+Z)(X-Z) =X²-Y²+(Y²-Z²)-(X²-Z²) =X²-Z²-(X²-Z²) =0

(x+(y-z))(x-(y-z))=x²-(y-z)²=x²-y²+2yz-z²

(x+y-z)(x-y-z) =[(x-z)+y][(x-z)-y] =(x-z)²-y² =x²-2xz+z²-y² 很高兴为您解答,祝你学习进步>学习宝典】团队为您答题。 有不明白的可以追问!如果您认可我的回答。 请点击下面的【选为满意回答】按钮。 如果有其他...

(y-z)³+(z-x)³+(x-y)³ =(y-z+z-x)[(y-z)²+(y-z)(z-x)+(z-x)²] -(y-x)³ =(y-x)[(y-z)²+(y-z)(z-x)+(z-x)²] -(y-x)³ =(y-x)[(y-z)²+(y-z)(z-x)+(z-x)²-(y-x)²] =(y-x)[(y-z)...

(x+y+z)(x-y-z)-(x-y+z)(x+y-z) =(x+y+z)[x-(y+z)]-[x-(y-z)][x+(y-z)] =x²-2x(y+z)+(y+z)²-x²+2x(y-z)-(y-z)² =2x(y-z-y-z)+[(y+z)²-(y-z)²] =-4xz+(2yz+2yz) =4yz-4xz

(x+y-z+1)(x-y+z+1) =(x+1)²-(y-z)² =x²+2x+1-y²+2yz-z²

(x-y+z)(x+y-z) =[x-(y-z)][x+(y-z)] =x²-(y-z)² =x²-y²+2yz-z² 1/2(1+1/2)(1+1/4)(1+1/16) =(1-1/2)(1+1/2)(1+14)(1+1/16) =(1-1/4)(1+1/4)(1+1/16) =(1-1/16)(1+1/16) =1-1/256 =255/256

x+z=2y 解: (x-z)²-4(x-y)(y-z)=0 (x-y+y-z)²-4(x-y)(y-z)=0 (x-y)²+(y-z)²+2(x-y)(y-z)-4(x-y)(y-z)=0 (x-y)²+(y-z)²-2(x-y)(y-z)=0 [(x-y)-(y-z)]²=0 (x+z-2y)²=0 x+z-2y=0 x+z=2y

这是初中一年级完全平方公式的知识。 公式:(a-b)²=a²-2ab+b² 本题中,a=x+y,b=z (x+y-z)² =[(x+y)-z]² =(x+y)²-2z(x+y)+z² -2z(x+y)就是这么来的,直接套用完全平方公式就可以得到。

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